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Question
The number of structural and configurational isomers of a bromo compound, C5H9Br, formed by the addition of one mole HBr to 2-pentyne respectively are
The number of structural and configurational isomers of a bromo compound, C5H9Br, formed by the addition of one mole HBr to 2-pentyne respectively are
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Solution
The correct option is B 2 and 4
Addition of HBr of 2-pentyne gives two structural isomers.
CH3−C≡C−CH2CH3HBr−−−→CH3C(Br)=CHCH2CH3+CH3CH=C(Br)CH2CH3
Each one of these will exist as a pair of geometrical isomers. Thus, there are two structural and four configurational isomers.
Hence, the correct answer is option (b).
Addition of HBr of 2-pentyne gives two structural isomers.
CH3−C≡C−CH2CH3HBr−−−→CH3C(Br)=CHCH2CH3+CH3CH=C(Br)CH2CH3
Each one of these will exist as a pair of geometrical isomers. Thus, there are two structural and four configurational isomers.
Hence, the correct answer is option (b).Suggest Corrections
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