The number of structural and configurational isomers of a bromo compound, C5H9Br, formed by the addition of HBr to 2−pentyne respectively x and y. Find the value of x+y.
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Solution
When HBr adds on to 2−pentyne it gives two structural isomers i.e., I and II.
Each one of these (i.e., I and II) exsits as a pair of geometrical isomers (cis and trans). Thus, we have two structural and four configurational isomers.