The number of structural isomers of $C_{3} H_{5} B r_{3}$ is :

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 5
5 structural isomers are possible.
$- C - C - C B r_{3}$
$- C - C B r - C B r_{2}$
$- C - C B r_{2} - C B r$
$- B r C - C - C B r_{2}$
$- C B r - C B r - C B r$

Suggest Corrections

Similar questions

C_{3} H_{5} B r_{3}

C_{6} H_{14}

C_{6} H_{14}

C_{6} H_{14}

Join BYJU'S Learning Program