The number of students enrolled in a school is $2000$ . If the enrollment increases by $5$ % every year, how many students will be there after two years?

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Solution

Let number of students be $P$
Therefore $P = 2000$
Rate of increment $(R) = 5 %$
Time $(T) = 2$
We need to find amount $(A)$

The formula is given by

$A = P (1 + \frac{R}{100})^{T}$

$= 2000 (1 + \frac{5}{100})^{2}$

$= 2000 (\frac{21}{20})^{2}$

$= \frac{2000 \times 21 \times 21}{20 \times 20}$

$= 2205$

Number of students after $2$ years is $2205$

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The number of students enrolled in a school is 2000. If the enrollment increases by 5% every year, how many students will be there after two years?

Let number of students be P Therefore P=2000Rate of increment (R)=5%Time (T)=2We need to find amount (A)The formula is given byA=P(1+R100)T =2000(1+5100)2 =2000(2120)2 =2000×21×2120×20 =2205Number of students after 2 years is 2205

The number of students enrolled in a school is $2000$ . If the enrollment increases by $5$ % every year, how many students will be there after two years?