wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of subshells and orbitals possible for the principal quantum number 5 is

A
5, 25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
25, 5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4, 16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5, 5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5, 25
n is principal quantum number
l is azimuthal quantum number
l ranges from 0 to (n-1)
Given n = 5 So l = 0,1,2,3,4
Number of subshells = 5 (5s,5p,5d,5f,5g)
For s, orbital = 1
For p, orbital = 3
For d, orbital = 5
For f, orbital = 7
For g, orbital = 9
So, total number of orbitals = 25
We can also use the formula as number of orbital = n2
For n = 5, number of orbitals = 25

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon