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Question
The number of such numbers which are divisible by two and five (all digits are not different) is
The number of such numbers which are divisible by two and five (all digits are not different) is
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Solution
The correct option is D 100
The numbers which are divisible by 2 and 5 are the multiples of 10.
Hence the ending digit has to be 0.
However the starting digit cannot be 0.
Now
_ _ _ 0.
Hence number of ways of filling the first place will be 4, the second place will be 5 and 3rd place will be 5, since repetition of digits are allowed.
Hence total number of the numbers which are divisible by 2 and 5 are
4×5×5
=100
The numbers which are divisible by 2 and 5 are the multiples of 10.
Hence the ending digit has to be 0.
However the starting digit cannot be 0.
Now
_ _ _ 0.
Hence number of ways of filling the first place will be 4, the second place will be 5 and 3rd place will be 5, since repetition of digits are allowed.
Hence total number of the numbers which are divisible by 2 and 5 are
4×5×5
=100
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