The correct option is D 500
For a number to be even it must have 0,2,4,6,8 at the end.
Since it has to be a 4 digit number, 0 cannot be at the starting of the number.
Considering the number
ABCD
The number of ways of filling the first place will be 4.
The number of ways of filling the second place will be 5.
The number of ways of filling the 3rd place will be 5
And the number of filling the 4th place will be 5. Since repetition of the numbers are allowed.
Hence total number of permutations will be
=4×5×5×5
=4×125
=500.