Question

The number of sulphur atoms present in $0.2$ mole of sodium thiosulphate is: $(N=$ Avogadro number)

• A. $4N$
• B. $0.2N$
• C. $0.4N$
• D. $0.1N$

Answer 1

The correct option is C $0.4N$

Formula of Sodium Thiosulphate is ${Na}_2{S}_2{O}_3$

Number of Sulphur Atoms = Atomicity x No of Moles x N

= 2 x 0.2 x N

= 0.4 N

Option $C$ is correct.