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Question

The number of tangents to the curve x3/2+y3/2=a3/2, where the tangents are equally inclined to the axes, is

A
2
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B
1
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C
0
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D
4
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Solution

The correct option is B 1
dydx=1 (where x is equally inclined)
32x1/2+3/2y1/2dydx=0
dydx=xy=1
xy=1
x=y
x=y
x3/2+x3/2=a3/2
2x3/2=a3/2
x=a22/3
y=a22/3
only one tangent.

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