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Question

The number of tangents which can be drawn from the point$$ (1,2)$$ to the circle  $${x^2} + {y^2} - 2x - 4y + 4 = 0$$ are:


A
1
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B
2
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C
3
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D
0
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Solution

The correct option is A $$0$$
Point $$(1,\ 2)$$

Circle $$=x^{2}+y^{2}-2x-4y+4=0------(1)$$

put point $$(x,\ y)$$ in eq $$-----(1)$$

$$(1)\ +4-2-8+4$$

$$-1 < 0$$

Therefore, point lies inside the circle 

$$\therefore \ $$ No. of triangles drawn $$=0$$


Mathematics

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