The number of tangents which can be drawn from the point $(1, 2)$ to the circle $x^{2} + y^{2} - 2 x - 4 y + 4 = 0$ are:

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is A $0$
Point $(1, 2)$

Circle $= x^{2} + y^{2} - 2 x - 4 y + 4 = 0 - - - - - - (1)$

put point $(x, y)$ in eq $- - - - - (1)$

$(1) + 4 - 2 - 8 + 4$

$- 1 < 0$

Therefore, point lies inside the circle

$∴$ No. of triangles drawn $= 0$

Suggest Corrections

Similar questions

x^{2} + y^{2} + 2 x - 4 y + 4 = 0

x^{2} + y^{2} - 2 x - 4 y + λ = 0

l a m b d a

An infinite number of tangents can be drawn from (1, 2) to the circle $x^{2} + y^{2} - 2 x - 4 y + λ = 0,$ then $λ =$

x^{2} + y^{2} - 2 x + 4 y = 0

(1, 2)

x^{2} + y^{2} - 2 x - 4 y + λ = 0.

λ

Join BYJU'S Learning Program