The number of terms in the expansion of (1+5√2x)9+(1−5√2x)9 is
A
5
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B
7
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C
9
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D
10
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Solution
The correct option is A 5 S=(1+5√2x)9+(1−5√2x)9 Let k=5√2 Then the above binomial expansion changes to S=(1+k)9+(1−k)9 =[1+9C1k+9C2k2+...9C9k9]+[1−9C1k+9C2k2−9C3k3...−9C9k9] =2[1+9C2k2+9C4k4+9C6k6+9C8k8] Hence in total 5 terms will be there.