The number of terms in the expansion of $(4 x^{2} - 16 x + 16)^{5}$ is

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Solution

Given : $(4 x^{2} - 16 x + 16)^{5} = {(2 x - 4)^{2}}^{5} = (2 x - 4)^{10}$
We know, the number of terms in $(a + b)^{n}$ is $n + 1.$
$\Rightarrow 10 + 1 = 11$

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