The number of terms in the expansion of(a+b+c)n, where n∈N .
Find the number of terms.
The total number of terms (N) in the expansion of (a1+a2+a3+...+ak)n is given by, Ck-1n+k-1.
We have to find the number of terms in the expansion of(a+b+c)n.
Here k=3
C3-1n+3-1=C2n+2⇒=(n+2)!2!(n+2-2)!⇒=(n+2)!2(n!)⇒=(n+2)(n+1)n!2·n!⇒=(n+2)(n+1)2
Hence, the number of terms is (n+1)(n+2)2.
Find the number of terms in the expansion of (a+b+c)n.
The number of terms in the expansion of (a+b+c)n
will be