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Question

The number of terms in the expansion of(a+b+c)n, where nN .


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Solution

Find the number of terms.

The total number of terms (N) in the expansion of (a1+a2+a3+...+ak)n is given by, Ck-1n+k-1.

We have to find the number of terms in the expansion of(a+b+c)n.

Here k=3

C3-1n+3-1=C2n+2=(n+2)!2!(n+2-2)!=(n+2)!2(n!)=(n+2)(n+1)n!2·n!=(n+2)(n+1)2

Hence, the number of terms is (n+1)(n+2)2.


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