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Question

The number of terms in the expansion of (1+3x+3x2+x3)6 is

A
18
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B
9
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C
19
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D
24
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Solution

The correct option is C 19
(1+3x+3x2+x3)6
=[(1+x)3]6
=[1+x]6(3)
=(1+x)18
Hence total number of terms will be 18+1=19terms

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