The number of terms in the expansion of (x3+9x2+27x+27)25 is
A
25
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B
26
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C
75
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D
76
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Solution
The correct option is D76 Here, x3+9x2+27x+27=(x+3)3 ⇒(x3+9x2+27x+27)25=((x+3)3)25 ⇒(x+3)75 Here, n=75, we know that number of terms in the binomial expansion is n+1=76