CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of terms in the expansion of (x3+9x2+27x+27)25 is

A
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
26
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
76
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 76
Here, x3+9x2+27x+27=(x+3)3
(x3+9x2+27x+27)25=((x+3)3)25
(x+3)75
Here, n=75, we know that number of terms in the binomial expansion is n+1=76

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon