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Multinomial Expansion

The number of...

Question

The number of terms in the expansion of $(x + y + z)^{10}$ is

88

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55

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66

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77

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Solution

The correct option is C $66$
Given expansion is $(x + y + z)^{10}$
So, the number of terms
$=^{n + r - 1} C_{r - 1} =^{10 + 3 - 1} C_{3 - 1} =^{12} C_{2} = \frac{12 \times 11}{2} = 66$

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