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Question

The number of terms in the expansion of (x+y+z)power n

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Solution

Dear Student,
BY BINOMIAL EXPANSION:

(x+a)n=nC0xna0+nC1xn-1a1+nC2xn-2a2+..........+nCnx0an

No. of terms in (x+y+z)^n
⇒[x+(y+z)]^n
⇒[x+(y+z)]^n=nC0xn (y+z)0+nC1xn-1 (y+z)1+nC2xn-2(y+z)2+.....nCnx0(y+z)n
​​​​

=>No. of terms in (x+y+z)n
⇒(n+1)/2*[(n+2)/2]
⇒(n+1)/2(n+2)/2

Regards
Manshi Arora


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