1
Question
The number of terms in the expansion of (x+y+z+u)5 is:
The number of terms in the expansion of (x+y+z+u)5 is:
Open in App
Solution
The correct option is A 56
Number of terms in the expansion of (x1+x2+....+xn)n is n+r−1Cn
the number of terms in the expansion of (x+y+z+u)5=5+4−1C5=8C5=56
56
Number of terms in the expansion of (x1+x2+....+xn)n is n+r−1Cn
the number of terms in the expansion of (x+y+z+u)5=5+4−1C5=8C5=56
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
