Question

The number of terms in the sequence $3,7,11,\dots ,407$ is

• A. $102$
• B. $103$
• C. $104$
• D. $101$

Answer 1

The correct option is A $102$

Given: $3,7,11,\dots ,407$
So, the given sequence is A.P. with $a=3,d=4$
Now, $T_n=407$
$\Rightarrow a+(n-1)d=407\Rightarrow 3+(n-1)\times 4=407\Rightarrow n=102$