The number of terms in the sequence 3-7-11- - 407 is

The correct option is A 102Given: 3, 7, 11, …, 407 So, the given sequence is A.P. with nbsp;a = 3, d = 4 Now, T_n = 407 ⇒ a+(n 1)d = 407 ⇒ 3+(n 1)× 4 = 407 ...

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Standard XI

Mathematics

Arithmetic Progression

The number of...

Question

The number of terms in the sequence $3, 7, 11, \dots, 407$ is

102

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103

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104

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101

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Solution

The correct option is A $102$
Given: $3, 7, 11, \dots, 407$
So, the given sequence is A.P. with $a = 3, d = 4$
Now, $T_{n} = 407$
$\Rightarrow a + (n - 1) d = 407 \Rightarrow 3 + (n - 1) \times 4 = 407 \Rightarrow n = 102$

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The number of terms in the sequence 3,7,11,…,407 is

The correct option is A 102Given: 3,7,11,…,407 So, the given sequence is A.P. with a=3, d=4 Now, Tn=407 ⇒a+(n−1)d=407⇒3+(n−1)×4=407⇒n=102

The number of terms in the sequence $3, 7, 11, \dots, 407$ is

The correct option is A $102$
Given: $3, 7, 11, \dots, 407$
So, the given sequence is A.P. with $a = 3, d = 4$
Now, $T_{n} = 407$
$\Rightarrow a + (n - 1) d = 407 \Rightarrow 3 + (n - 1) \times 4 = 407 \Rightarrow n = 102$