wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The number of terms of G.P. 3,32,34,required to give the sum 3069512 is

Open in App
Solution

a=3,r=12
So, Sn=3[1(1/2)n]112=6[112n]
Now 6[112n]=3069512
112n=1023102412n=11024=1210n=10

flag
Suggest Corrections
thumbs-up
84
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon