Question

The number of tetrahedral voids in a FCC lattice is

• A. $4$
• B. $6$
• C. $8$
• D. $2$

Answer 1

The correct option is C $8$

In FCC, tetrahedral voids are created at the conjuction of one atom at corner and three atoms at the face center. One body diagonal has 2 tetrahedral voids and there are total 4 body diagonals.
So, the number of tetrahedral voids in a FCC is $8$.