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Question

The number of the points in the cartesian plane with integral coordinates satisfying the inequalities |x|k , |y|k , |xy|k is (where kN)

A
(k+1)3k3
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B
(k+2)3(k+1)3
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C
(k2+1)
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D
None of these
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Solution

The correct option is A (k+1)3k3
|x|k
kxk (i)
and |y|k
kyk (ii)
and |xy|k
|yx|k
kyxk
xkyx+k (iii)


Number of the points having integral coordinates
=(2k+1)22[k+(k1)+...+2+1]
=3k2+3k+1
=(k+1)3k3

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