The number of the points on the curve $y = x^{3} - 11 x + 5$ at which the tangent are parallel to the line y = x + 5 is

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Solution

The correct option is B
2

$\frac{d y}{d x} = 1 \Rightarrow 3 x^{2} - 11 = 1 \Rightarrow x = \pm 2$

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Similar questions

y = x^{3} - 2 x^{2} - x

y = 3 x - 2

y = x^{3} - 11 x + 5

y = x - 11

y = x^{3} - 11 x + 5

y = x - 11.

y = x^{3} - 11 x + 5

y = x - 11

\frac{x^{2}}{9} - \frac{y^{2}}{4} = 1

5 x + 2 y - 3 = 0

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