The number of three digit numbers having only two consecutive digits identical is

153

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162

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180

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161

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Solution

The correct option is B 162
When first two consecutive digits are 11, 22 etc = $9 \times 9 = 81$
When last two consecutive digits are 0,0 = 9
When last two consecutive digits are $11, 22, 33, \dots = 9 \times 8 = 72$
Total 81 + 9 + 72 = 162

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