The number of three element subsets of {1, 2 ......10} sum of whose elements is even is :

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Solution

The correct option is B
60

a + b + c = even
Case 1 : All taken are even : ⁵C₃ = 10 Case 2 : One even + 2 odd : ⁵C₁× ⁵C₂= 50
Total = 10 + 50 = 60

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