Question

The number of times the digit $5$ will be written while listing the integers from $1$ to $1000$ is $xyz$ then the value of $(x+y+z)$ is equal to

Answer 1

$1+9+8+1+9\times 9+8\times 9+9+9+8+1$

$\Rightarrow 271times$

$\therefore xyz=271$

$\therefore x=2;y=7;z=1$

$\therefore x+y+z=2+7+1$

$x+y+z=10$