The correct option is B 4
Three is the minimum number of nucleotides per codon needed to encode 20 amino acids. 20 amino acids are encoded by combinations of 3 nucleotides. If a codon were two nucleotides, the set of all combinations could encode only. 4x4 = 16 amino acids. With three nucleotides, the set of all combinations can encode. 4x4x4 = 64 amino acids i.e., 64 different combinations of four nucleotides taken three at a time.