Question

The number of turns in primary and secondary coils of a transformer is $50$ and $200$, respectively. If the current in the primary coil is $4A$, then the current in the secondary coil is

• A. $1A$
• B. $2A$
• C. $4A$
• D. $5A$

Answer 1

The correct option is A

$1A$

Step 1: Given Data

Number of turns in the primary coil $N_P=50$

Number of turns in the secondary coil $N_S=200$

Current in the primary coil $I_P=4A$

Let $I_s$ be the current in the secondary coil.

Step 2: Formula Used

$\frac{N_P}{N_S}=\frac{I_S}{I_P}$

Step 3: Calculate Current in Secondary Coil

We know that in a transformer,

$$\begin{gathered} \frac{N_P}{N_S}=\frac{I_S}{I_P} \\ \Rightarrow I_S=\frac{N_P}{N_S}\times I_P \end{gathered}$$

Upon substituting the values we get,

$$\begin{gathered} I_S=\frac{50}{200}\times 4 \\ =1A \end{gathered}$$

Hence, the current in the secondary coil is $1A$ and therefore the correct answer is option (A).