Question

The number of turns in primary and secondary coils of an ideal transformer is $50$ and $200$ respectively. If the current in the primary coil is $4\text{A}.$ The current in the secondary coil is-

• A. $1\text{A}$
• B. $2\text{A}$
• C. $4\text{A}$
• D. $5\text{A}$

Answer 1

The correct option is A $1\text{A}$

Given,

$N_p=50;N_s=200;I_p=4\text{A}$

In a transformer,

$\frac{V_s}{V_p}=\frac{N_s}{N_p}=\frac{I_p}{I_s}$

$\frac{200}{50}=\frac{4}{I_s}$

$I_s=1\text{A}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(A\right)$ is the correct answer.