wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of turns in the coil of an a.c. generator is 5000 and the area of the coil is 0.25 m2. The coil is rotated at the rate of 100 cycle per second in a magnetic field of 0.2 T. The peak value of the emf generated is nearly

A
157 kV
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
220 kV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
440 kV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
786 kV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 157 kV
Peak value of emf generated by a.c. generator is,

ε=BANω=BAN(2πf)

ε=0.2×0.25×5000×2×3.14×100

ε=157×103 V (or)

ε=157 kV

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (A) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric Generator
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon