Question

The number of turns in the coil of an AC generator ar e$100$ and its cross-sectional area is $2.5m^2$. The coil is revolving in a uniform magnetic field of strength $0.3T$ with the uniform angular velocity of $60rad/s$. The value of maximum value produced is _____kV

• A. $1.25$
• B. $4.50$
• C. $6.75$
• D. $2.25$

Answer 1

The correct option is B $4.50$

The induced emf in a coil is given by

$e=NBA\omega \sin \omega t$

for maximum induced emf $e_{max}$

$\sin \omega t=1$
So $e_{max}=NBA\omega$

putting values
$e_{max}=100\times 0.3\times 2.5\times 60$
$e_{max}=4.5kV$