The number of turns in the primary coil of a transformer are $100$ and that in the secondary coil are $200$ . What type of transformer is it? If the input voltage in the primary coil of the transformer is $200 V$ , find the output voltage in the secondary coil of the transformer.

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Solution

Step 1: Given data
Number of turns in the primary coil $N_{p} = 100$
Number of turns in the secondary coil $N_{s} = 200$
Input voltage in the primary coil is $V_{p} = 200 V$
Step 2: Finding the type of transformer
It is given that $N_{p} = 100$ and $N_{s} = 200$
We know that when $N_{s} > N_{p}$ , the transformer is a step-up transformer.
Step 3:Finding the output voltage in the secondary coil of the transformer.
We know that, $\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{p}}$ where $N_{s}$ and $N_{p}$ is number of turns in the secondary coil and primary coil respectively and $V_{s}$ and $V_{p}$ is voltage in the secondary and primary coil of the transformer.
Substituting the given values in
$\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{p}}$
$\frac{200}{100} = \frac{V_{s}}{200}$
Cross multiplying
$V_{s} = \frac{200}{100} \times 200 V_{s} = 400 V$
Hence, the transformer is a step-up transformer and the output voltage in the secondary coil of the transformer is $400 V$ .

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