Question

The number of unbonded electrons present on N in NO is

• A. 2
• B. 3
• C. 4

Answer 1

The correct option is B 3

For O to achieve octet, it needs to share only 2 electrons with Nitrogen (7N).

$\therefore :\stackrel{\cdot }{N}=\stackrel{\cdot \cdot }{O}:$

After this oxygen has 8 electrons, but N is left with only 7 electrons.

$\therefore$ Oxygen shares one more of its electron to form an odd electron bond