The number of unpaired electrons in a chromic ion $C r^{3 +}$ $($ atomic number $24)$ is:

6

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4

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3

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1

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Solution

The correct option is C $3$
$_{24} C r = {1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{5} {4 s}^{1}$
${_{24} C r}^{3 +} = {1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{3}$

Hence, it has 3 unpaired electrons in 3d orbitals.

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