Question

The number of unpaired electrons in $M{n}^{4+}$($z=$25) is :

• A. four
• B. two
• C. five
• D. three

Answer 1

The correct option is D three

Total electrons in $M{n}^{4+}=25-4=21.$

E.C. of $M{n}^{4+}=1s^2,2s^2,2p^6,3s^2,3p^6,3d^3$

So, 3 unpaired electrons.

Therefore, the correct option is D.