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VBT Tetrahedral vs Square Planar

The number of...

Question

The number of unpaired electrons in $[N i C l_{4}]^{2 -}, N i (C O)_{4}$ and $[C u (N H_{3})_{4}]^{2 +}$ respectively are:

2, 2, 1

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2, 0, 1

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0, 2, 1

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2, 2, 0

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Solution

The correct option is A 2, 0, 1
REF.Image.
$∵ C l^{-}$ is a weak ligand. So, there is no pairing of electrons.
No.of unpaired $e^{-} = 2$
CO is a strong ligand. So there is pairing of electrons
No. of unpaired electron = 0
No. of unpaired electron = 1

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