The number of unpaired electrons in the complex ion [CoF6]3− is
(Atomic number Co=27)
A
4
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B
0
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C
2
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D
3
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Solution
The correct option is A 4 In complex ion [CoF6]3−, Co is present at +3 oxidation state 27Co=1s2,2s22p6,3s23p63d7,4s2 Co3+=1s2,2s22p6,3s23p63d6
Electrons will not paired up because F− is a weak field ligand. Thus the number of unpaired electrons in 3d sub-shell of [CoF6]3−| is 4.