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Question

The number of unpaired electrons present in the species [Fe(H2O)5NO]2+ which is formed during 'brown ring' test is

A
2
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B
3
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C
4
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D
5
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Solution

The correct option is B 3
The oxidation state of Fe in the complex is +1 and Coordination number of Fe is 6. The configuration of Fe is 3d64s2 and that of Fe+ is 3d64s1. Now, since the NO+ is a strong field ligand so only one pairing of 3d and 4s electron occurs and hence the number of unpaired electron corresponds to n=3.Hence the correct option is B.

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