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Question

The number of value of in set of value of r for which 23Cr+2.23Cr+1+23Cr+225C15 is

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Solution

We know nCr+nCr1=n+1Cr
23Cr+23Cr+1+23Cr+1+23Cr+225C15
23Cr+1+23Cr+23Cr+2+23Cr+125C15
24Cr+1+24Cr+225C15
24Cr+2+24Cr+125C15
25Cr+225C15
The Inequity holds when
r=8,9,10,11,12,13
Hence, number of value of 'r' which satisfies
the given Equation is '6'.

1074777_1183693_ans_7f5af55b2d794121ac0ae9e13f00b7d0.png

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