The number of value(s) of ′x′ which satisfies the equation x2+4|x|+12=0 is/are
A
0
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B
1
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C
2
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D
infinite
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Solution
The correct option is A0 Given x2+4|x|+12=0 ⇒|x|2+4|x|+4+8=0 ⇒(|x|+2)2+8=0
Since, (|x|+2)2>0 (always) ⇒(|x|+2)2+8>0 (always) ∴x2+4|x|+12=0 has no real solution.