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Question

The number of values of a for which (a23a+2)x2+(a25a+6)x+a24=0 is an identity in x is-

A
0
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B
2
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C
1
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D
3
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Solution

The correct option is C 1
Equation is a identity if all its coefficients are equal to zero simultaneously

a23a+2=0

a=2,1

a25a+6=0

a24=0

a=±2

coefficients are equal to zero simultaneously when a=2

Therefore only one value of 'a' the equation is identity in x

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