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Byju's Answer
Standard X
Mathematics
Quadratic Formula
The number of...
Question
The number of values of
a
for which
(
a
2
−
3
a
+
2
)
x
2
+
(
a
2
−
5
a
+
6
)
x
+
a
2
−
4
=
0
is an identity in
x
is-
A
0
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B
2
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C
1
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D
3
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Solution
The correct option is
C
1
Equation is a identity if all its coefficients are equal to zero simultaneously
⇒
a
2
−
3
a
+
2
=
0
⇒
a
=
2
,
1
⇒
a
2
−
5
a
+
6
=
0
⇒
a
2
−
4
=
0
⇒
a
=
±
2
⇒
coefficients are equal to zero simultaneously when
a
=
2
Therefore only one value of 'a' the equation is identity in
x
Suggest Corrections
0
Similar questions
Q.
The number of integral values of
a
for which
(
a
2
−
3
a
+
2
)
x
2
+
(
a
2
−
5
a
+
6
)
x
+
a
2
−
4
=
0
is an identity in
x
is
Q.
For how many values of
a
, equation
(
a
2
−
3
a
+
2
)
x
2
+
(
a
2
−
4
)
x
+
a
2
−
a
−
2
=
0
is an identity
Q.
The value of
a
for which the equation
(
a
2
−
3
a
+
2
)
x
2
+
(
a
2
−
5
a
+
4
)
x
+
(
a
2
−
1
)
=
0
has more than two roots is:
Q.
Assertion :If
(
a
2
−
4
)
x
2
+
(
a
2
−
3
a
+
2
)
x
+
(
a
2
−
7
a
+
10
)
=
0
is an identity, then the value of
a
is
2
. Reason: If
a
−
b
=
0
, then
a
x
2
+
b
x
+
c
=
0
is an identity.
Q.
If
(
a
2
−
1
)
x
2
+
(
a
−
1
)
x
+
a
2
−
4
a
+
3
=
0
be an identity in
x
, then the value of a is/are ?
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