The number of values of k for which the system of equations $(k + 1) x + 8 y = 4 k$
$k x + (k + 3) y = 3 k - 1$ has infinitely many solutions, is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

infinite

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1
For infinitely many solution,
$\frac{k + 1}{k} = \frac{8}{k + 3} = \frac{4}{3 k - 1}$
$\Rightarrow \frac{8}{k + 3} = \frac{4}{3 k - 1}$
$\Rightarrow 5 k = 5$
$\Rightarrow k = 1$

Suggest Corrections

Similar questions

(k + 1) x + 8 y = 4 k, k x + (k + 3) y = 3 k - 1

k

(k + 1) x + 8 y = 4 k

k x + (k + 3) y = 3 k - 1

\Rightarrow

\Rightarrow

Join BYJU'S Learning Program