The number of values of k for which the system of equations have infinite solution- (k+1)x + 8y = 4k kx + (k+3)y = 3k – 1

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Infinite

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Solution

The correct option is B 1
option (b)

Sol:- k+1/k = 8/k+3 = 4k/3k-1

Only k = 1 satisfies this.

2nd method: - For infinite solution

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Similar questions

k

(k + 1) x + 8 y = 4 k

k x + (k + 3) y = 3 k - 1

The number of values of k for which the system of equations $(k + 1) x + 8 y = 4 k, k x + (k + 3) y = 3 k - 1$ has infinitely many solution is

(k + 1) x + 8 y = 4 k

k x + (k + 3) y = 3 k - 1

k

2 x + 3 y = k

(k - 1) x + (k + 2) y = 3 k

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