The number of values of $k$ for which the system of equations
$(k + 2) x + 10 y = k$
$k x + (k + 3) y = k - 1$
has infinitely many solutions, is?

0

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Solution

The correct option is A $0$
For infinite solution
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$
$\frac{K + 1}{K} = \frac{8}{K + 3} = \frac{4 K}{3 K - 1}$
For No value of $K$ these equation
$∴$ Zero values.

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