The number of values of k. for which the system or equations:
(k+1) x +8y = 4k
kx + (k+3) y = 3k-1
has no solution, is
A
infinite
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B
1
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C
2
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D
3
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Solution
The correct option is B 1 From the given system, we have k+1k=8k+3≠4k3k−1 (\therefore\) system has no solution) ⇒k2+4k+3=8k ⇒k=1,3
If k =1 then 81+3≠4.12 Which is false.
And if k=3
then 86≠4.39−1 which is true, ∴k=3
Hence for only one value of k. System has no solution.