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Question

The number of values of k. for which the system or equations:
(k+1) x +8y = 4k
kx + (k+3) y = 3k-1
has no solution, is

A
infinite
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B
1
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C
2
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D
3
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Solution

The correct option is B 1
From the given system, we have
k+1k=8k+34k3k1 (\therefore\) system has no solution)
k2+4k+3=8k
k=1,3
If k =1 then 81+34.12 Which is false.
And if k=3
then 864.391 which is true, k=3
Hence for only one value of k. System has no solution.

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