The correct option is B 1
[x2−(k−2)x+k2][x2+kx+(2k−1)] for this expression to be a perfect square there can two possible ways:
1) When both the quadratic expression are perfect square for a particular value,
For that to happen k−2=2k⇒k=−2
Now for k=−2 in the second expression we get x2−2x−5 which is not a perfect square.
2) The other is when both the quadratic equation are same,
∴−(k−2)=k⇒k=1k2=2k−1⇒k=1
Therefore, at k=1 the expression is perfect square.