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Question

The number of values of k for which [x2−(k−2)x+k2][x2+kx+(2k−1)] is a perfect square is

A
2
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B
1
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C
0
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D
none of these
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Solution

The correct option is B 1
[x2(k2)x+k2][x2+kx+(2k1)] for this expression to be a perfect square there can two possible ways:
1) When both the quadratic expression are perfect square for a particular value,
For that to happen k2=2kk=2
Now for k=2 in the second expression we get x22x5 which is not a perfect square.
2) The other is when both the quadratic equation are same,
(k2)=kk=1k2=2k1k=1
Therefore, at k=1 the expression is perfect square.

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