The correct option is A 2
f(x)=x+3|log2x|−6
For this function to be defined, the denominator cannot equal to zero.
|log2x|−6≠0⇒|log2x|≠6⇒log2x≠±6⇒x≠26,2−6⇒x≠64,164
We know that, for log2x to be defined
x>0
When x∈[0,1]
Therefore, in x∈[0,1] the function is not defined at 2 values that are x=0,164.