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Question

The number of values of x in the interval [0,3π] satisfying the equation 2sin2x+5sinx3=0 is

A
4
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B
6
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C
1
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D
2
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Solution

The correct option is B 6

2sin2x+5sinx3=0(sinx+3)(2sinx1)=0sinx=12x=π6,5π6,7π6,11π6,13π6,17π6


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